Cirrus Logic CS485 Instrukcja Użytkownika Pobierz pdf (Strona 19)

CS485G Spring 2015 19

1 int absdiff(int x, int y)

2 {

3 int result;

4 if (x > y) {

5 result = x-y;

6 } else {

7 result = y-x;

8 }

9 return result;

10 }

absdiff:

pushl %ebp # save base pointer

movl %esp,%ebp # new base pointer

movl 8(%ebp), %edx # d = x

movl 12(%ebp), %eax # a = y

cmpl %eax, %edx # x <> y ?

jle .L6 # jump if x <= y

subl %eax, %edx # x = x - y

movl %edx, %eax # a = x - y

jmp .L7 # jump

.L6:

subl %edx, %eax # a = y - x

.L7:

popl %ebp # restore %ebp

ret # return

10. Example:

1 int absDiff(int x, int y)

2 {

3 int result;

4 if (x <= y) goto elsepoint;

5 result = x-y;

6 goto exitpoint;

7 elsepoint:

8 result = y-x;

9 exitpoint:

10 return result;

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